MHB How Do You Find Multiple Solutions for Trigonometric Equations?

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SUMMARY

This discussion focuses on finding multiple solutions for trigonometric equations, specifically for the equations $$\sin(Ø)=0.8$$, $$\sin(Ø)=-0.58$$, $$\cos(Ø)=-0.55$$, and $$\cos(Ø)=0.71$$. The method involves using the unit circle to visualize the solutions, where the first solution is found using the inverse sine function, $$\theta=\sin^{-1}(0.8)$$. The second solution for sine is derived using the identity $$\sin(\pi-\theta)=\sin(\theta)$$. For cosine equations, a vertical line is drawn to identify intersections with the unit circle.

PREREQUISITES
  • Understanding of trigonometric functions (sine and cosine)
  • Familiarity with the unit circle concept
  • Knowledge of inverse trigonometric functions
  • Ability to apply trigonometric identities
NEXT STEPS
  • Learn how to use the unit circle for cosine equations
  • Study the properties of trigonometric identities
  • Practice finding solutions for $$\sin(Ø)$$ and $$\cos(Ø)$$ in different quadrants
  • Explore the application of inverse trigonometric functions in solving equations
USEFUL FOR

Students preparing for trigonometry quizzes, educators teaching trigonometric concepts, and anyone seeking to improve their understanding of solving trigonometric equations.

bsmithysmith
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I have a quiz on Friday and I'm not understanding one part of the section;

find all the solutions for $$ sin(Ø)=0.8$$

and I'm not understanding how to find the other solution. This may be an easier one, but there's also:$$Sin(Ø)=-.58$$
$$Cos(Ø)=-.55$$
$$Cos(Ø)=.71$$Need help finding two solutions for each!
 
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For $\sin(\theta)=0.8$, draw a unit circle, and then draw the line $y=0.8$. Now, from the center of the unit circle, draw two rays, one to each point of intersection between the circle and the line. The angle subtended by each ray and the positive $x$-axis in the counter-clockwise direction are your two solutions, given that we are looking for solutions in:

$$0\le\theta<2\pi$$

For the first quadrant angle, use you calculator to find an approximation for:

$$\theta=\sin^{-1}(0.8)$$

Now, can you see how to use this value to determine the second quadrant solution? It has to do with the identity:

$$\sin(\pi-\theta)=\sin(\theta)$$

From your drawing, can you "see" how this identity has to be true?
 
MarkFL said:
For $\sin(\theta)=0.8$, draw a unit circle, and then draw the line $y=0.8$. Now, from the center of the unit circle, draw two rays, one to each point of intersection between the circle and the line. The angle subtended by each ray and the positive $x$-axis in the counter-clockwise direction are your two solutions, given that we are looking for solutions in:

$$0\le\theta<2\pi$$

For the first quadrant angle, use you calculator to find an approximation for:

$$\theta=\sin^{-1}(0.8)$$

Now, can you see how to use this value to determine the second quadrant solution? It has to do with the identity:

$$\sin(\pi-\theta)=\sin(\theta)$$

From your drawing, can you "see" how this identity has to be true?

SWEET! Helped a bunch! Thank You!
 
For the remaining problems use a similar technique, except where you have the cosine function, use a vertical line instead of a horizontal line for the intersections to help you visualize where the solution(s) are. :D
 

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