How do you find the direction and magnitude from a nucleus?

AI Thread Summary
The discussion focuses on calculating the electric field and force related to a nucleus with 65 protons. For part (a), the electric field is calculated using the formula E = KQ/d^2, resulting in a value of 2.44e30 N at a distance of 4.9 x 10^-10 m. Clarification is sought regarding the charge of 65 protons, emphasizing that it does not equate to 65 coulombs. Part (b) requires calculating the force exerted on an electron at the same distance, which involves using the previously calculated electric field. Understanding the charge of the nucleus is essential for both calculations.
itsmarasilly
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Homework Statement



The nucleus of an atom has a charge of 65 protons.

(a) What are the direction and magnitude of the electric field at 4.9 x 10^-10 m from the nucleus?

(b) What are the direction and magnitude of the force exerted on an electron located at this distance?


Homework Equations


E= KQ/d^2
K= 9 x 10^9


The Attempt at a Solution



(a) (9 x 10^9)(65)/(4.9 x 10^-10)^2
= 2.44e30 N

Please help clarify if (a) is correct, and what exactly is (b) asking, if any different from (a)?
 
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I think you need to understand what the charge of 65 protons is.
http://en.wikipedia.org/wiki/Proton

It is not 65 coulombs that are the units of the equation you used.

Having found the field, then b) is asking you to find the force.
 

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