How Do You Find the Minimum Length of Segment AB in a Coordinate Plane?

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To find the minimum length of segment AB, which is formed by a line through the point (2,2) intersecting the x- and y-axes, one must first define the function representing the length of AB. The minimum length occurs when the derivative of this function equals zero, not greater than zero. Utilizing geometric principles, such as similar triangles, can aid in formulating the equation of the line. It is suggested to express the x-intercept as (X, 0) to derive the necessary equations. Ultimately, minimizing the square of the length can simplify the problem.
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A line through the point (2,2) cuts the x- and y- axes at points A and B respectively. Find the Minimum length of the segment AB.

Im really stuck on this problem. I know that minimum lengh is when f'>0.

Could you guys give me a lift off here?

ty
 
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Haven't I seen this problem before? :)
 
http://www.twilightus.net/adam/optimization.JPG
I think this image is self explanatory and should get you off to a good start.

BTW, this is only one way of doing it, and there are many!

Now you have one defined length, and you can get everything else with this, good luck!
 
dsb_101 said:
A line through the point (2,2) cuts the x- and y- axes at points A and B respectively. Find the Minimum length of the segment AB.
Im really stuck on this problem. I know that minimum lengh is when f'>0.
ty
No, you don't know that- that makes no sense because you haven't said what f is. It is also true that the minimum (or maximum) of any function occurs when the derivative of that function is equal[\b] to 0 (not > 0).

So first decide what function you want to minimize. One way to do that is to look at moose's picture and think about similar triangles. Another is to assume the x-intercept of the line is at (X, 0) (X is some unknown constant) and write the equation of the line.

Hint: Since length is always positive, length will be a minimum when (length)2 is minimum.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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