How Do You Integrate \(\int \frac{x-3}{x^2+2x-5}dx\) with Complex Roots?

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SUMMARY

The integration of the function \(\int \frac{x-3}{x^2+2x-5}dx\) involves a quadratic denominator that can be simplified using the method of completing the square. The quadratic equation \(x^2 + 2x - 5\) has a positive discriminant of 24, indicating it has real and distinct roots. To effectively integrate, one should rewrite the denominator in the form \((x+a)^2 + c\) before proceeding with the integration process.

PREREQUISITES
  • Understanding of integration techniques, specifically for rational functions.
  • Familiarity with completing the square for quadratic expressions.
  • Knowledge of the quadratic formula and discriminants.
  • Basic algebraic manipulation skills.
NEXT STEPS
  • Learn how to complete the square for various quadratic equations.
  • Study integration techniques for rational functions, including partial fraction decomposition.
  • Explore the application of the quadratic formula in solving equations.
  • Review the concept of discriminants and their implications for root types in polynomials.
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Students and educators in calculus, mathematicians focusing on integration techniques, and anyone seeking to enhance their understanding of rational function integration.

Tasy
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[itex]\int \frac{x-3}{x^2+2x-5}dx[/itex]

How integrate this task?

[itex]x^2+2x-5=0[/itex]

[itex]D=24[/itex], so I can't get real root.
 
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Tasy said:
[itex]\int \frac{x-3}{x^2+2x-5}dx[/itex]

How integrate this task?

[itex]x^2+2x-5=0[/itex]

[itex]D=24[/itex], so I can't get real root.

OK, that line with the discriminant made no sense. The discriminant is greater than zero, so clearly the quadratic does have real, distinct roots.

Hint: start off with completing the square on the denominator. In other words, express the denominator in the form [itex](x+a)^2 + c[/itex] and go from there.
 
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