How Do You Normalize an Angular Momentum State and Determine Lz Probabilities?

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kcasali
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Homework Statement



A particle is in an angular momentum state

Ψ(θ,φ) = |l=1,m=1> + 2|1,0> + 3|1,-1>

Normalize this state and find the probabilities for finding the system with its third component Lz with values hbar, 0, -hbar.



Homework Equations





The Attempt at a Solution



I know that to normalize the kets, I just have to multiply them by their bras, but I'm not sure if I multiply the entire equation by the same bra or how to multiply it by three different bras. (I'm also not sure if I'm even on the right track.)
 
kcasali said:

Homework Statement



A particle is in an angular momentum state

Ψ(θ,φ) = |l=1,m=1> + 2|1,0> + 3|1,-1>

Normalize this state and find the probabilities for finding the system with its third component Lz with values hbar, 0, -hbar.

- the coefficients 1, 2, and 3 are probability amplitudes. you know that if you square the probability amplitude, you get a probability. Right now, your probability adds up to 1^2 + 2^2 + 3^2. You want to do something to these coefficients so that their squares add up to 1... instead of 1^2 + 2^2 + 3^2. But you have to do the same thing to each amplitude so that their relative sizes don't change.
 
xcrunner2414 said:
- the coefficients 1, 2, and 3 are probability amplitudes. you know that if you square the probability amplitude, you get a probability. Right now, your probability adds up to 1^2 + 2^2 + 3^2. You want to do something to these coefficients so that their squares add up to 1... instead of 1^2 + 2^2 + 3^2. But you have to do the same thing to each amplitude so that their relative sizes don't change.

That makes sense, but where am I supposed to get the hbar and -hbar from? Am I missing something really obvious?
 
kcasali said:
That makes sense, but where am I supposed to get the hbar and -hbar from? Am I missing something really obvious?

- If you measure the particle to have z-component spin of hbar, that means it's in the |1,1> state. If its z-component is 0, it's in the |1,0> state. If its z-component is -hbar, it's in the |1,-1> state.
 
xcrunner2414 said:
- If you measure the particle to have z-component spin of hbar, that means it's in the |1,1> state. If its z-component is 0, it's in the |1,0> state. If its z-component is -hbar, it's in the |1,-1> state.

Ahhh, thank you! Am I on the right track to normalize the state initially?
 
Had the same problem quasite a while ago.
Did the same mistake.