How Do You Normalize an Angular Momentum State and Determine Lz Probabilities?

kcasali
Messages
12
Reaction score
0

Homework Statement



A particle is in an angular momentum state

Ψ(θ,φ) = |l=1,m=1> + 2|1,0> + 3|1,-1>

Normalize this state and find the probabilities for finding the system with its third component Lz with values hbar, 0, -hbar.



Homework Equations





The Attempt at a Solution



I know that to normalize the kets, I just have to multiply them by their bras, but I'm not sure if I multiply the entire equation by the same bra or how to multiply it by three different bras. (I'm also not sure if I'm even on the right track.)
 
Physics news on Phys.org
kcasali said:

Homework Statement



A particle is in an angular momentum state

Ψ(θ,φ) = |l=1,m=1> + 2|1,0> + 3|1,-1>

Normalize this state and find the probabilities for finding the system with its third component Lz with values hbar, 0, -hbar.

- the coefficients 1, 2, and 3 are probability amplitudes. you know that if you square the probability amplitude, you get a probability. Right now, your probability adds up to 1^2 + 2^2 + 3^2. You want to do something to these coefficients so that their squares add up to 1... instead of 1^2 + 2^2 + 3^2. But you have to do the same thing to each amplitude so that their relative sizes don't change.
 
xcrunner2414 said:
- the coefficients 1, 2, and 3 are probability amplitudes. you know that if you square the probability amplitude, you get a probability. Right now, your probability adds up to 1^2 + 2^2 + 3^2. You want to do something to these coefficients so that their squares add up to 1... instead of 1^2 + 2^2 + 3^2. But you have to do the same thing to each amplitude so that their relative sizes don't change.

That makes sense, but where am I supposed to get the hbar and -hbar from? Am I missing something really obvious?
 
kcasali said:
That makes sense, but where am I supposed to get the hbar and -hbar from? Am I missing something really obvious?

- If you measure the particle to have z-component spin of hbar, that means it's in the |1,1> state. If its z-component is 0, it's in the |1,0> state. If its z-component is -hbar, it's in the |1,-1> state.
 
xcrunner2414 said:
- If you measure the particle to have z-component spin of hbar, that means it's in the |1,1> state. If its z-component is 0, it's in the |1,0> state. If its z-component is -hbar, it's in the |1,-1> state.

Ahhh, thank you! Am I on the right track to normalize the state initially?
 
Nevermind, I got it. Thank you!
 
Had the same problem quasite a while ago.
Did the same mistake.
 
Back
Top