How Do You Simplify Complex Exponential Expressions Using Euler's Formula?

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SUMMARY

The discussion focuses on simplifying the expression e^(i6θ) * [(1 + e^(-i10θ))/(1 + e^(i2θ))] using Euler's formula. Participants emphasize the importance of applying Euler's formula, e^(iθ) = cos(θ) + i*sin(θ), and standard trigonometric identities to transform the expression into a form involving cosines. A key point is the clarification that e^(-iwt) is equivalent to cos(wt) - i*sin(wt), not -cos(wt) - i*sin(wt). The goal is to express the final result solely in terms of cosines.

PREREQUISITES
  • Understanding of Euler's formula (e^(iθ) = cos(θ) + i*sin(θ))
  • Familiarity with complex numbers and their properties
  • Knowledge of trigonometric identities
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the application of Euler's formula in complex analysis
  • Learn about trigonometric identities and their proofs
  • Practice simplifying complex exponential expressions
  • Explore the relationship between complex exponentials and sinusoidal functions
USEFUL FOR

Students studying complex analysis, mathematics enthusiasts, and anyone looking to deepen their understanding of trigonometric simplifications using Euler's formula.

Larrytsai
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Homework Statement


Simplify the expression

e^(i6theta)[ (1+e^(-i10theta))/(1+e^i2theta)]

Answer should be in terms of cosines

but i don't know how to start this problem? :S

Also, does e^(-iwt) = - coswt -jsinwt?

K so I am thinking about Eulers formula, and I get an expression with Sines and cosines not just cosines =s
 
Last edited:
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Hi Larrytsai! :smile:

(have a theta: θ and try using the X2 icon just above the Reply box :wink:)

hint: use Euler's formula and standard trigonometric identities to simplify 1 + e2iθ :wink:

(oh, and e-iθ = cosθ - isinθ)
 

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