How Do You Simplify This Complex Absolute Value Expression?

AI Thread Summary
The discussion revolves around simplifying a complex absolute value expression involving exponential terms. The original expression is \[\left[\left|(\alpha + k)^{2}e^{-2i \alpha a} - (\alpha - k)^{2}e^{2i \alpha a}\right|\right]^{2}. The key insight shared is that the absolute value of the exponential term simplifies to 1, which aids in the overall simplification. The final simplified form of the expression is \((\alpha + k)^{4} + (\alpha - k)^{4} - (\alpha^{2} - k^{2})^{2}(e^{4i \alpha a} + e^{-4i \alpha a})\). The original poster successfully resolved the complexity of the problem.
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Homework Statement



I need to simplify the expression below. The absolute value is throwing me off

<br /> \left[\left|(\alpha + k)^{2}e^{-2i \alpha a} - (\alpha - k)^{2}e^{2i \alpha a}\right|\right]^{2}<br />

Homework Equations



I know \left|e^{ix}\right| = 1

The Attempt at a Solution



I know this eventually simplifies to:
<br /> (\alpha + k)^{4} + (\alpha - k)^{4} - (\alpha^{2} - k^{2})^{2}(e^{4i \alpha a} + e^{-4i \alpha a})<br />
 
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Don't worry about it. I figured it out.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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