How Do You Sketch These Vector Fields in the XY-Plane?

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Homework Help Overview

The original poster is tasked with sketching several vector fields in the xy-plane, specifically F(r) = 2r, F(r) = -r/||r||³, and F(x,y) = 4xi + xj. The discussion revolves around understanding how to represent these vector fields visually in a two-dimensional context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the direction and magnitude of the vectors, suggesting that identifying symmetries may be helpful. There is also a focus on how to interpret the 3D nature of the first vector field when sketching it in the xy-plane, with questions about the representation of the vector components.

Discussion Status

Participants are actively engaging with the problem, clarifying notation and exploring how to adapt the 3D vector field to a 2D sketch. Some guidance has been offered regarding the interpretation of the vector components, but multiple interpretations of the vector fields are still being explored.

Contextual Notes

There is some confusion regarding the notation and the implications of representing a 3D vector field in a 2D plane, particularly concerning the role of the z-component and how it affects the representation of r.

-EquinoX-
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Homework Statement



I am asked to sketch the following vector field in the xy-plane

(a) F(r) = 2r


(b) F(r) = -r/||r||3


(c) F(x,y) = 4xi + xj

Homework Equations





The Attempt at a Solution



Can someone please give me some hints on how to proceed
 
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hi EquinoX

first I would look at the direction and magitudes of the vectors & see if you can spot any symmetries

a good way to start is to sketch the vector at several points as well
 
yes but for F(r) = 2r this is a 3D vector field, so if I am asked to sketch it in an xy plane, do I just look at the i + j direction? and is 2r basically just 2xi + 2yj + 2zk?

because r is xi + yj + zk?
 
Last edited:
Yeah i think that should do

r = sqrt(x^2 + y^2 + z^2) and in the xy plane z = 0, so this shouldn't affect your r anyway
 
so r = sqrt(x^2)i + sqrt(y^2)j ?
 
sorry bit of confusion over notation
|r| = sqrt(x^2 + y^2 + z^2)

r = xi + yj + zk
 
I am asking 2r?
 

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