How Do You Solve a Linear Algebra Slope Problem?

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To solve the linear algebra slope problem, first, determine the slope (m) of the line given by the equation 6y + 3x = 3 by rearranging it into slope-intercept form (y = mx + b). The slope of any line perpendicular to this will be -1/m. Next, create the equation of a line that passes through the point (8, -1) using the perpendicular slope. To find the intersection of the two lines, solve the equations simultaneously, and finally, calculate the distance from the point (8, -1) to the intersection point. This process will yield the required distance and sketch of the situation.
DethRose
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Hey i have a homework assignment due and have no idea how to answer 1 of the questions

the question is

Find m and recal m perpendicular = -1/m. Also sketch the situation showing what the required distance is.

6y+3x=3 ; (8,-1)

all assistance is much appreciated

thanks
 
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I think you need to find the distance between the point and the line. The distance is a line coming out of the point and is perpendicular to the first line.
 
1) To find the slope, m, of 6y+ 3x= 8, solve for y: the equation will be in the form y= mx+ b.

2) Of course, any line perpendicular to that line will have slope
-1/m. What is the equation of a line through (8,-1) with slope
-1/m? (Use the value of m you found in 1).)

3) Where do those two lines cross? Solve the two equations simultaneously.

4. What is the distance from (8, -1) to the point you found in 3)?
 
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