Engineering How Do You Solve a Parallel Circuit Problem with Unequal Currents?

AI Thread Summary
The discussion revolves around solving a parallel circuit problem involving three resistors (R1, R2, R3) with an equivalent resistance of 720 ohms and unequal currents (I1, I2, I3). The relationships between the currents are established, with I2 being three times I1 and I3 six times I1. Participants discuss the application of the parallel circuit equation and Ohm's law to find the resistances, emphasizing that higher current corresponds to lower resistance. Confusion arises regarding the lack of voltage information, but it is clarified that the voltage across all resistors is the same in a parallel circuit. Ultimately, the participant expresses understanding after receiving guidance on the relationships and equations involved.
Peter Ke
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Homework Statement


Resistor R1, R2, R3 are connected in parallel, have an equivalent resistance of 720(ohms). The currents are labeled I1, I2,and I3. I2 is 3x the value of I1, and I3 is 6x the value of I1. Calculate R1, R2, R3.

Homework Equations


I used the parallel circuit equation. 1/RT=1/R1+1/R2...

The Attempt at a Solution


[/B]
I tried to solve it like this...

1/720= 1/R1+1/(1/3R1)+1/(1/6R1)---> 720=R1+3R1)+6R1-----> 720= 10R1-----> R1=72 ohms.
I know I made a mistake or I have been following the wrong path. Please help I really don't understand this question. Thank You!
 
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Peter Ke said:

Homework Statement


Resistor R1, R2, R3 are connected in parallel, have an equivalent resistance of 720(ohms). The currents are labeled I1, I2,and I3. I2 is 3x the value of I1, and I3 is 6x the value of I1. Calculate R1, R2, R3.

Homework Equations


I used the parallel circuit equation. 1/RT=1/R1+1/R2...

The Attempt at a Solution


[/B]
I tried to solve it like this...

1/720= 1/R1+1/(1/3R1)+1/(1/6R1)---> 720=R1+3R1)+6R1-----> 720= 10R1-----> R1=72 ohms.
I know I made a mistake or I have been following the wrong path. Please help I really don't understand this question. Thank You!
Can you upload a copy of the problem/schematic? :smile:
 
berkeman said:
Can you upload a copy of the problem/schematic? :smile:

I'm so sorry, this was a word problem that came from a classwork that the teacher gave me. There was no diagram that came with it.
I have seen one person who tried to solve it in this website ---> https://answers.yahoo.com/question/index?qid=20140911191648AArMp36
but he didn't explain it, he just showed his equation so I still didn't understand how he arrived on his answers.

If you could help, then thank you!
 
Peter Ke said:
1/720= 1/R1+1/(1/3R1)+1/(1/6R1)
With the same voltage across the resistors (parallel circuit), when the current is higher, is the resistance higher or lower?
Then look at the equation you generated. Does it indicate higher or lower resistances for the associated currents?
 
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When the current is higher the resistance is lower because current and resistance are inversely proportional.
Based on what you said, my equation indicates that it has higher resistance when I simplify it.
 
Peter Ke said:
When the current is higher the resistance is lower because current and resistance are inversely proportional.
Based on what you said, my equation indicates that it has higher resistance when I simplify it.
Equivalent resistance of the parallel combination is less than the least of R1, R2 and R3.
Voltage across all the resistors is same since they are in parallel. Use Ohm's law to find the resistances.
 
Yea but the amount of voltage is not given so how do I even use Ohm's Law?
 
Peter Ke said:
Yea but the amount of voltage is not given so how do I even use Ohm's Law?
V=IR..
So, I1R1=I2R2=I3R3..
You know the relation amongst I1, I2 and I3.
 
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cnh1995 said:
V=IR..
So, I1R1=I2R2=I3R3..
You know the relation amongst I1, I2 and I3.
Thank you so much! I got it!
 

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