How Do You Solve a System of Linear ODEs with Equal Second Derivatives?

s_j_sawyer
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Homework Statement



Solve this system of linear ODEs:

1) x''(t) = x + y
2) y''(t) = x + y


Just fyi, this is part of a much larger problem but I need to solve this system!

Homework Equations



See above.

The Attempt at a Solution



Okay so I think the most logical way to solve this would be to set x''(t) = y''(t).

Then
x''(t) = y''(t)
x' = y' + c1
x = y + c1t + c2

which implies

3) x'' = 2x - c1t - c2
4) y'' = 2y + c1t + c2

But I am not sure what to do from here. Apparently there should be 4 arbitrary constants in the final answer. But wouldn't solving x'' for x give you 2 and then solving y'' for y give you two more?

Thanks for any help.
 
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Did you find the eigenvalues and eigenvectors? What is the general solution to this linear system of ODEs? Yes you will end up with 4 constants but that's the minor step
 
You could also write it as a vector equation
<br /> \vec x&#039;&#039;(t) = \left(\begin{array}{cc} 1&amp;1\\1&amp;1\end{array}\right)\vec x(t)<br />
and go on from there.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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