How do you solve ln x=1/2x-1/2?

[johann1301]

How do you solve ln x=1/2x-1/2?

Please show every step.

Thanks.

 

[jedishrfu]

We can't help you if you don't shop some work, we're not here to simply show every step of a problem.

 

[Ray Vickson]

How do you solve ln x=1/2x-1/2?

Please show every step.

Thanks.

You need to learn to use parentheses. What you have written reads as
\ln \, x = \frac{1}{2x} - \frac{1}{2}. If that is what you meant, then fine (although you could make it clearer by writing (1/2x) - 1/2 on the right). If you meant to write
\ln \, x = \frac{1}{2x - 1/2}, then you need brackets, like this: 1/(2x - 1/2). If you meant something else entirely, you really will have to write it correctly and readably.

And, as others have said, you need to do some of your own work first, and show what you have done.

RGV

 

[micromass]

Locked for not providing effort. Feel free to report such threads.