You can do it by parts. Consider that
\frac{d}{dx} x \ln x = \ln x + 1
#3
KSCphysics
31
0
hrmm... i see what your saying..
#4
iluvsr20s
13
0
wouldn't it just be 1/u?
unless that little dash is a negative sign mean your are integrating 1/ln(u) then I'm not sure but i think it would just be u then, but i am probably wrong
Hi everybody
If we have not any answers for critical points after first partial derivatives equal to zero, how can we continue to find local MAX, local MIN and Saddle point?. For example: Suppose we have below equations for first partial derivatives:
∂ƒ/∂x = y + 5 , ∂ƒ/∂y = 2z , ∂ƒ/∂z = y
As you can see, for ∇ƒ= 0 , there are not any answers (undefined)