How Do You Solve Putnam 2005 B3 with a Polynomial Guess?

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SUMMARY

The discussion focuses on solving the 2005 Putnam competition question B3 using polynomial guesses versus a more analytical approach involving substitutions. The original poster successfully guessed a polynomial solution but expressed discomfort with the analytical method that substitutes x with a/x. The analytical solution involves calculating derivatives and eliminating parameters, specifically the variable 'a'. Understanding this elimination process is crucial for grasping the solution's elegance.

PREREQUISITES
  • Understanding of polynomial functions and their properties
  • Familiarity with calculus, particularly derivatives and second derivatives
  • Knowledge of substitution methods in algebra
  • Experience with problem-solving in mathematical competitions, specifically the Putnam exam format
NEXT STEPS
  • Study the method of substitution in calculus, focusing on variable transformations
  • Learn about polynomial interpolation and its applications in competitive mathematics
  • Explore the concept of derivatives and their role in function analysis
  • Review previous Putnam problems to understand common solving techniques
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Mathematics students, competitive problem solvers, and anyone preparing for the Putnam exam will benefit from this discussion, particularly those interested in advanced problem-solving techniques and analytical methods.

SeReNiTy
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Hey guys, I was doing some Putnam questions for fun and came across something strage to me. In the 2005 Putnam competition, question B3, link provided below:

http://www.unl.edu/amc/a-activities/a7-problems/putnam/-pdf/

I solved it by guessing a polynomial solution and then verifying the co-efficients, but in their solutions they have a more analytical approach where they let x = a/x. Now I'm a bit uncomfortable with this substitution so i let y = a/x, and preceeded to compute their solution. The point i get stuck is after they calculate the second derivative, they somehow eliminate all the a's. Could something explain that step? Its probably trivial and I'm just not putnam material!
 
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They are just using what f '(x) is equal to, and a little bit of algebra.
 
Now I'm a bit uncomfortable with this substitution
Think of a similar situation: if you were told that

f(x) = x^2 + 3x + 5,​

would you be comfortable answering the question

What is f(1/x)?​
 

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