How Do You Solve sqrt(3) sec x = -2 for x in Radians?

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To solve the equation sqrt(3) sec x = -2, the first step is to rewrite it as cos x = - (sqrt 3)/2. The angles where cosine equals -(√3)/2 are 5π/6 and 7π/6. Since sine and cosine functions are periodic with a period of 2π, the general solutions include 7π/6 + 2πn, where n is any integer. The discussion emphasizes the importance of showing attempts in problem-solving to facilitate assistance. Understanding the periodic nature of trigonometric functions is crucial for finding all solutions.
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Find Exact Radian Solution OR to nearest 100th of a radian

sqrt(3) sec x = -2
 
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You need to at least show an attempt here before anyone can help you. Look at a graph of sec(x).
 
Dick said:
You need to at least show an attempt here before anyone can help you. Look at a graph of sec(x).

well, would the first step be changing it to
cos x = - (sqrt 3)/2

?
 
hailey51 said:
well, would the first step be changing it to
cos x = - (sqrt 3)/2

?

Yes.

For what angles is cosine = -(√3)/2 ?
 
SammyS said:
Yes.

For what angles is cosine = -(√3)/2 ?

This is where I get confused...
it's not ∏/6 right? because it's negative
so it could be the 5∏/6 ?
and is that the only answer?
 
Since sine and cosine are periodic with period 2\pi, no that is not the only solution.
 
HallsofIvy said:
Since sine and cosine are periodic with period 2\pi, no that is not the only solution.

Oh, would the other solution be 7π/6 +2πn ?
 
hailey51 said:
Oh, would the other solution be 7π/6 +2πn ?

Right.
 
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