How Do You Solve This Complex Integral?

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SUMMARY

The discussion focuses on solving the integral \int^{√x}_{1}\frac{t^{3}+t-1}{t^{2}(t^{2}+1)} dt. A user suggests using partial fractions decomposition to rewrite the integrand as \frac{A}{t} + \frac{B}{t^2} + \frac{Ct + D}{t^2 + 1}. This method allows for the identification of constants A, B, C, and D, enabling the integration of simpler functions derived from the decomposition.

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  • Understanding of integral calculus
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  • Knowledge of rational functions
  • Ability to perform variable substitution in integrals
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Students studying calculus, particularly those tackling complex integrals, and educators looking for effective teaching methods for integral techniques.

skyturnred
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Homework Statement



[itex]\int^{√x}_{1}[/itex][itex]\frac{t^{3}+t-1}{t^{2}(t^{2}+1)}[/itex] dt

Homework Equations





The Attempt at a Solution



So I first start by expanding the bottom part of the fraction to t[itex]^{4}[/itex]+t[itex]^{2}[/itex], and letting u equal to that. Then du=4t[itex]^{3}[/itex]+2t dt. I move the common multiple of 2 over to the other side so that it is (1/2)du=2t[itex]^{3}[/itex]+t dt. I cannot find out how to relate that to the numerator (although I am so close).

Can someone please help? Thanks!
 
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skyturnred said:

Homework Statement



[itex]\int^{√x}_{1}[/itex][itex]\frac{t^{3}+t-1}{t^{2}(t^{2}+1)}[/itex] dt

Homework Equations





The Attempt at a Solution



So I first start by expanding the bottom part of the fraction to t[itex]^{4}[/itex]+t[itex]^{2}[/itex], and letting u equal to that. Then du=4t[itex]^{3}[/itex]+2t dt. I move the common multiple of 2 over to the other side so that it is (1/2)du=2t[itex]^{3}[/itex]+t dt. I cannot find out how to relate that to the numerator (although I am so close).

Can someone please help? Thanks!
Do you know partial fractions decomposition? That seems to me to be the way to go. Using that technique you rewrite (t3 + t - 1)/(t2(t2 + 1) as the sum of three rational expressions of the form
[tex]\frac{A}{t} + \frac{B}{t^2} + \frac{Ct + D}{t^2 + 1}[/tex]

The idea is to find constants A, B, C, D so that the new representation is identically equal to the original rational expression. Once you find the constants, then integrate the sum of simpler functions.
 

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