mathematician121212
y′′−8y′+ 16y= cos(πt)δ(t−1)y(0) = 0, y′(0) = 0.
This sub-forum is for new member introductions only, not for questions.mathematician121212 said:y′′−8y′+ 16y= cos(πt)δ(t−1)y(0) = 0, y′(0) = 0.