How do you take Velocity from Acceleration?

AI Thread Summary
To find velocity from an acceleration vs. time graph, calculate the area under the curve, which represents the change in velocity. It's essential to know the initial velocity or the velocity at another specified time to determine the final velocity accurately. If the initial velocity is not provided, the calculation will be incomplete. Ensure that the units are consistent when performing these calculations. Understanding these concepts is crucial for solving related homework problems effectively.
charan1
Messages
40
Reaction score
0
For my HW question I have to take the velocity from an acceleration vs time graph at a certain time.

How do I do this? I was sure that the velocity was the area underneath the curve but its not coming out right at all.

Please help! Thanks
 
Physics news on Phys.org
The area under the acceleration graph gives the change in velocity. You still need to know what the velocity was initially, or at some other specified time.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top