How Do You Validate the Second Part of This System of Linear Equations?

AI Thread Summary
The discussion revolves around validating the second part of a system of linear equations, specifically finding the maximum value of a given expression after determining the values of λ and μ. The value of λ was found to be 8, and μ was later calculated to be 36. The user initially struggled with the validation process but ultimately derived expressions for y and z based on the infinite solutions of the system. By substituting these values into the expression, they successfully demonstrated that the maximum value is indeed 272. The problem was resolved using substitution and trigonometric identities, confirming the initial claim.
AGNuke
Gold Member
Messages
455
Reaction score
9
If the system of Linear Equations
x+y+z=6
x+2y+3z=14
2x+5y+\lambda z=\mu
has infinite number of solution in x, y, z

I need to find out two things
1. The value of λ
2. Maximum value of (\mu x+\lambda y-20z)sin^2\theta+(\lambda x+\mu y+64z)cos2\theta, \theta \in \mathbb{R} is 272

I used the Matrix method of AX=B to find out λ by solving for A=0; I got the answer 8, and it is correct.

Now my catch is to validate the second question. It is given true, I just need to validate. I tried to solve it with the three existing equations but I was unable to get answer.
 
Last edited:
Physics news on Phys.org
AGNuke said:
If the system of Linear Equations
x+y+z=6
x+2y+3z=14
2x+5y+\lambda z=\mu
has infinite number of solution in x, y, z

I need to find out two things
1. The value of λ
2. Maximum value of (\mu x+\lambda y-20z)sin^2\theta+(\lambda x+\mu y+64z)cos2\theta, \theta \in \mathbb{R} is 272

I used the Matrix method of AX=B to find out λ by solving for A=0; I got the answer 8, and it is correct.
That isn't quite correct- first you haven't told us what "A" is! More important you mean det(A)= 0, not A= 0.

Now my catch is to validate the second question. It is given true, I just need to validate. I tried to solve it with the three existing equations but I was unable to get answer.
 
A is the coefficient matrix which is present when we try to solve the system of equations using matrix.

A=\begin{bmatrix}<br /> 1 &amp;1 &amp;1 \\ <br /> 1 &amp; 2 &amp;3 \\ <br /> 2 &amp;5 &amp;\lambda <br /> \end{bmatrix}

and yes, I meant |A|=0, my bad.

Whatever that may be, I found out the value of λ and I need to find answer to my second question. I am on it, but haven't made progress.
 
AGNuke said:
A is the coefficient matrix which is present when we try to solve the system of equations using matrix.

A=\begin{bmatrix}<br /> 1 &amp;1 &amp;1 \\ <br /> 1 &amp; 2 &amp;3 \\ <br /> 2 &amp;5 &amp;\lambda <br /> \end{bmatrix}

and yes, I meant |A|=0, my bad.

Whatever that may be, I found out the value of λ and I need to find answer to my second question. I am on it, but haven't made progress.

You also need to determine the value of μ (because if you don't have the correct value the system will have no solutions at all). Once you know λ and μ you have an optimization problem in the 4 variables x,y,z,θ, subject to linear restrictions on x,y,z. This can be tackled via Lagrange multiplier methods, or in some other way that handles constraints. At that point the problem is more suitable for the "Calculus and Beyond" Forum.

RGV
 
Last edited:
μ can be determined by solving the three given equations, at which point, it returns the value 36.

We know λ and we know μ, I think we are good to go and find the answer.

UPDATE: I got my answer. I just found out y=4-2x and z=x+2; since the system has infinite solutions. I substituted y and z in the asked equation, got -8sin2θ + 272cos2θ. Then made sinθ=0 and cos2θ=1. Proved the statement right. :wink:
 
Last edited:
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top