How Does a Bug Affect the Spin of a CD?

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A CD spinning at 420 rpm slows to 280 rpm after a bug drops onto it, located 4.4 cm from the center. The problem requires calculating the ratio of the bug's mass to the mass of the CD using the principle of conservation of angular momentum. The initial angular momentum of the system must equal the final angular momentum after the bug lands. The discussion emphasizes the importance of applying the correct equations to solve for the mass ratio. Understanding these concepts is crucial for solving similar physics problems.
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Homework Statement


A CD (radius 6.0 cm) is spinning freely with an angular velocity of 420 rpm when a bug drops onto the CD a distance 4.4 cm from the center. If the CD slows to 280 rpm, what is the ratio of the bug's mass to the mass of the CD? (Ignore the effect of the hole in the center of the CD.)



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The Attempt at a Solution

 
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Hi dorian_stokes! :wink:

Use conservation of angular momentum …

what do you get? :smile:
​
 

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