How Does a Bullet Passing Through a Block Affect Speed and Energy?

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A bullet weighing 5.00g and traveling at 400 m/s impacts a 1.00-kg block on a frictionless surface, compressing a spring with a force constant of 900 N/m as it passes through. The block moves 5.00 cm after the impact, indicating energy transfer. Mechanical energy is not conserved during the collision due to the transformation of some kinetic energy into internal energy from friction and deformation. After the collision, the block's kinetic energy is converted into potential energy in the spring. The discussion emphasizes the need to analyze the collision and spring compression separately to understand energy conversion.
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I have been dueling with this problem for a hour or so now...

a 5.00g bullet moving with an initial speed of 400 m/s is fired into and passes through a 1.00-kg block. The block, initially at rest on a frictionless, horizontal surface, is connected to a spring with a force constant of 900 n/m. If the block moves 5.00cm to the right after impact, find (a) the speed at which the bullet emerges from the block and (b) the mechanical energy converted into internal energy in the collision.

questions I have:
1. What is converting mechanical energy?
2. Can you use conservation of energy here...i.e: whatever energy it took to compress the spring 5cm will be lost, and then you can find new speed from that? but still where is the internal energy coming from, the heat from the bullet?

thanks in advance!
 
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Treat the collision and the spring compression separately. During the collision, mechanical energy is not conserved (but what is?). Some of bullet's initial KE is transformed into internal energy due to friction/deformation within the wood.

After the collsion, the block has some KE, which ends up being transformed into spring PE.
 
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