How Does a Glass Beaker Withstand 1000 Degrees Celsius?

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A glass beaker can withstand high temperatures, such as 1000 degrees Celsius, due to several factors. The beaker may not actually be exposed to such high temperatures, as the reaction occurs at 120 degrees Celsius, with the interior temperature rising gradually. This slow and uniform temperature increase helps prevent excessive stress on the glass. Additionally, materials like borosilicate glass are designed to tolerate a wide range of temperatures. Understanding the specifics of heat transfer and reaction control is crucial to explaining the beaker's durability.
VASUbhagwat
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The temperature at which the process is carried out is around 120 degree centigrade, however in the interior , the reaction temperature goes to around 1000 degree centigrade. How is it then , that the glass beaker in which the synthesis is carried out does not crack even at such high temperatures. The temperature does not manifest itself on to the beaker.
 
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I don't have a clear idea of what "temperature doesn't manifest itself on to the beaker" means. If the beaker isn't exposed to 1000°, it doesn't seem like you actually have a question. If it does, your question is apparently (I'm guessing): Why in air at 120° doesn't a beaker at 1000° crack? The answer MIGHT be that the temperature rise of the beaker was slow and uniform enough to not cause excessive stress. The answer MIGHT be that beakers (kimax, pyrex, borosilicate, possibly even quartz) are designed to tolerate wide temperature ranges. Or perhaps the answer is that the beaker never comes into contact with 1000° material (or that the energy transfer of any such contact is very small). I will say that a reaction started at 120° and which runs up (exothermally) to 1000° is either out of control or must be controlled to be quite gradual - so gradual as to cast doubt on the attainment of 1000° (since there are heat losses involved).
 
Thanks for the reply. But I am not sure if these explanations could possibly be the truth. Just waiting for others to reply. Will keep you posted as well. Thanks once again for the reply.
 
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