moham_87
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inclined frictionless surface, end of string attached to polly (polly at top of the incline), and other end attached to a mass(m) and mass is attahed to one end of a spring, and the other end is attached to incline base
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A polly has radius (R) and moment of inertia (I), the surface is frictionless. The polly is wound clockwise to stretch the spring a distance (d) from its unstretched position and then released from rest. Find the angular speed when the spring is again unstretched or compressed.
Answer:
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(E)final = (E)initial
final[(0.5)mv^2 + (0.5)(I)w^2 + mgh + (0.5)kd^2] = initial [(0.5)mv^2 + (0.5)(I)w^2 + mgy + (0.5)kd^2]
where (w) is omega, (y) is inital vertical distance from object to ground
and (h) is final vertical distance from object to ground
v(initial)=0 , w(initial)=0 , v=Rw
from that:
w = sqrt [(2mg(h-y) + kd^2) / (mR^2 + I)]
is that right ?? please i really need to know
thnx a lot for any efforts
if u know how can i attach image file please inform me
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inclined frictionless surface, end of string attached to polly (polly at top of the incline), and other end attached to a mass(m) and mass is attahed to one end of a spring, and the other end is attached to incline base
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A polly has radius (R) and moment of inertia (I), the surface is frictionless. The polly is wound clockwise to stretch the spring a distance (d) from its unstretched position and then released from rest. Find the angular speed when the spring is again unstretched or compressed.
Answer:
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(E)final = (E)initial
final[(0.5)mv^2 + (0.5)(I)w^2 + mgh + (0.5)kd^2] = initial [(0.5)mv^2 + (0.5)(I)w^2 + mgy + (0.5)kd^2]
where (w) is omega, (y) is inital vertical distance from object to ground
and (h) is final vertical distance from object to ground
v(initial)=0 , w(initial)=0 , v=Rw
from that:
w = sqrt [(2mg(h-y) + kd^2) / (mR^2 + I)]
is that right ?? please i really need to know
thnx a lot for any efforts
if u know how can i attach image file please inform me
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