How Does a Spring Constant Affect Circular Motion on a Frictionless Table?

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The discussion centers on a physics problem involving a 2.3 kg mass connected to a spring with a spring constant of 180 N/m on a frictionless air table. The mass is set in circular motion at a speed of 1.6 m/s, but the radius of its path is unknown due to missing information about the spring's extension. Participants note the relevance of the equations F=ma and F=kx, emphasizing the need to relate the centripetal force to the spring force. The challenge lies in determining the radius of the circular path based on the provided data. Understanding the spring's extension is crucial for solving the problem effectively.
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Homework Statement


A 2.3 kg mass is connected to a spring with spring constant k = 180 N/m and unstretched length 17 cm. The pair are mounted on a frictionless air table, with the free end of the spring attached to a frictionless pivot. The mass is set into circular motion at 1.6 m/s .


Homework Equations


F=ma=(mv^2)/r F=kx ...not really sure


The Attempt at a Solution


I don't know how to even start it :(
 
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What do you need to get in the first place?
 
oh sorry! the radius of its path.
 
acg7160 said:
oh sorry! the radius of its path.

well you were not given the extension so you are missing some information. You were correct in equation mv2/r to kx.
 
That's all I was given...
 
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