How Does an Underground Oil Pocket Affect Gravity Measurements?

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To estimate the effect of an underground oil pocket on gravity measurements, one must consider the density of the oil and its volume. The relevant equation for calculating the gravitational force is not F = G (m1 + m2) / r^2, but rather involves the concept of gravitational attraction due to the mass deficit created by the oil pocket. By determining the mass of the oil pocket and comparing it to the surrounding Earth, the percentage difference in gravitational acceleration (g) can be calculated. The discussion emphasizes the need for the correct approach to quantify how gravity changes above the oil pocket. Understanding these principles is essential for accurate gravity measurement assessments in geophysical studies.
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Problem:
The center of a 1.30 km diameter spherical pocket of oil is 1.30 km beneath the Earth's surface.
Estimate by what percentage g directly above the pocket of oil would differ from the expected value of g for a uniform Earth? Assume the density of oil is 8.10x10^3 kg/m^3

Should I use the equation: F = G (m1 + m2) / r^2 ?
If not, which equation should I use?

Please help me to get started.

Thank you.
 
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Does this seem right way to find g and g'?
 

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