Merlin3189
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Is= Ip + I' , so when Is nearly equals Ip, then I' is small. That's what makes it so efficient.kiki_danc said:When the two currents are closest and they nearly cancel then the load would have minimal current (Is=Ip+ I' below).. why do you say it's more efficient?
The large common winding carries little current I', so the I2R loss is small in this large winding.
But don't think this is something that can be arranged for any transformer ratio. It's just that autotransformers are very efficient when making small changes in voltage, because then the current in the bulk of the winding is small. As the step up/down ratio increases, the autotransformer advantage decreases.