How Does Binary Star Mass Affect Orbital Period Calculation?

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In a binary star system where both stars have the same mass as the Sun and are separated by the same distance as Earth and the Sun, the orbital period calculation requires a modification of the standard formula. The standard equation assumes one mass is dominant, but in this case, both stars have equal mass, necessitating the use of a combined mass in the gravitational parameter. The correct approach involves using μ = G*(M + m), which simplifies to μ = 2*G*M for equal masses. This adjustment leads to a more accurate calculation of the period of revolution, which is found to be approximately 0.7 years. Understanding the impact of mass on orbital dynamics is crucial for accurate astrophysical calculations.
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In a certain binary-star system, each star has the same mass as our Sun, and they revolve about their center of mass. The distance between them is the same as the distance between Earth and the Sun. What is their period of revolution in years?
T^2=(4pi^2/GM)*r^3
I know that the mass of the sun is 1.9x10^30. I also found in my book that the distance between the Earth and the sun is 1.5 x 10^11. If I plug those numbers into the equation and I solve for the ratio between T/1y in seconds, I don't get the correct answer, which is 0.7 years. I'm assuming my mistake has to do with the distance between these two planets. Can anyone help me please?
 
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The problem is that the given expression for the period assumes that one of the masses is dominant (M >> m) and that the mass m of the smaller body can be ignored. Here both objects have the same mass.

The gravitational parameter μ = G*M is an approximation for when m << M. When this is not the case, take μ = G*(M + m), which in this instance will be G*(M + M), or μ = 2*G*M, since they are of equal mass M.
 
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