How Does Breathing Affect Water Vaporization and Caloric Loss?

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AI Thread Summary
The discussion revolves around calculating the water vapor content in inhaled and exhaled air, as well as the associated caloric loss due to vaporization. The saturation vapor densities at 68°F and 98.6°F are provided, leading to the determination of actual water vapor densities based on relative humidity. Participants confirm calculations for the grams of water contained in 10 liters of air, noting a change in water vapor content of +0.3535 grams per minute. The conversation emphasizes the need to calculate daily water loss and heat loss in kilocalories based on the vaporization of this water. Overall, the calculations and concepts discussed are aimed at understanding the physiological implications of breathing on water vaporization and energy loss.
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Homework Statement



If a person breathes 10 liters per minute of air at 68°F & 50% relative humidity, how much water per minute must the internal membranes supply to saturate this air at 98.6°F? If all of this moisture is subsequently exhaled, how much water per day is given off by the body in this process? If each gram of water extracts .58 kcals of energy as it is vaporized, how much daily heat loss in kcals (food calories) does this represent?


Homework Equations



Saturation Vapor Density at 68°F = 17.3g / m3
Saturation Vapor Density at 98.6°F = 44.0g / m3


The Attempt at a Solution



Yet another problem of subject matter our teacher has never touched on. I really don't understand how saturation and calories are even remotely associatable. We have some other values we need to plug in, so with any explanation on this problem, I should be able to work from there on the remaining problems.
 
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If the saturation water vapor density at 68F (20C) is 17.3 g/m^3, and the relative humidity of the water vapor in the air is 50%, what is the actual water vapor density in the inhaled air? How many grams of water are contained in 10 liters of this air?

If the saturation water vapor density at 98.6 F (37C) is 44.0 g/m^3 and the exhaled air is saturated (100% relative humidity), how many grams of water are contained in 10 liters of this exhaled air?

What is the change in the water vapor content between the inhaled air and exhaled air for 10 liters of air?

Chet
 
A. If the saturation water vapor density at 20°C is 17.3g/m3, and the relative humidity of the water vapor in the air is 50%, what is the actual water vapor density in the inhaled air?

Inhaled Water Vapor Density = (17.3*.5) = 8.65g/m3?


B. How many grams of water are contained in 10 liters of this air?

10 liters = .01m3

8.65g/m3 * .01m3 = .0865 grams?


C. If the saturation water vapor density at 37°C is 44.0g/m3 and the exhaled air is saturated (100% relative humidity), how many grams of water are contained in 10 liters of this exhaled air?

44g/m3 * .01m3 = .44 grams?


D. What is the change in the water vapor content between the inhaled air and exhaled air for 10 liters of air?

Inhaled Water Vapor - Exhaled Water Vapor = -.3535 grams (Water Vapor leaving the body)?


Would anyone mind giving me confirmation that I am going in the right direction with this? Also, using this information, I should now be able to answer the questions in my original post, which are:

• How much water per minute must the internal membranes supply to saturate this air at 98.6°F?
Found in D.?

• How much water per day is given off by the body in this process?
Find number of minutes in a day and multiply it by what we found in D.?

• How much daily heat loss in kcals (food calories) does this represent?
Take the total water loss per day and cross multiply with my original given rate of grams of water to kcals vaporized to find total kcals of heat loss per day?
 
All correct, except that +0.3535 gm water vapor leaving body per minute, not -0.3535. Otherwise, very nicely done.

Chet
 
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