How Does Conjugation Lower Energy and Increase Stability in Aromatic Compounds?

  • Thread starter Thread starter Johnleprekan
  • Start date Start date
  • Tags Tags
    Energy
AI Thread Summary
Conjugation in aromatic compounds lowers overall energy and increases stability due to the delocalization of electrons across multiple atoms. This delocalization allows for a more even distribution of electron density, which reduces the potential energy of the molecule. Aromatic compounds are particularly stable because they possess additional resonance structures compared to non-aromatic conjugated systems. Resonance structures illustrate the different ways electrons can be arranged within a molecule, highlighting that electrons are not fixed but rather spread out. This spreading of electrons contributes to the stability of the molecule, as it minimizes energy fluctuations and creates a more stable electronic configuration.
Johnleprekan
Messages
55
Reaction score
0
Can someone explain, possibly in layman's terms, how conjugation such as with aromatic compounds lowers the overall energy; making it more stable?

Could someone also explain why aromatic compounds are more stable than through conjugation alone and what the difference is?
 
Chemistry news on Phys.org
It has more resonance structures
 
Can you explain how resonance structures work?
 
Basically, molecules have electrons that are moving around, so the resonance structure tries to capture the fact that electrons are all around the molecule, and sometimes more electrons are near a certain element within the molecule.

http://en.wikipedia.org/wiki/Resonance_structure

More resonance structures means that the electrons are more spread out, so the molecule is more stable.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top