How Does Cooling Affect Pressure in a Sealed Water Container?

AI Thread Summary
Cooling a sealed water container from 2MPa to 40C affects the pressure due to changes in specific volume. The initial specific volume must be calculated to determine the final pressure accurately. As the container cools, the water will reach a state of saturation, resulting in a mixture of liquid and vapor. The final pressure can be derived from steam table properties at the new temperature. Understanding these principles is crucial for solving the problem effectively.
physea
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Homework Statement


1kg of water fills 151.1L of rigid container at pressure 2MPa. Then the container is cooled to 40C. What is the final pressure?

Homework Equations


Steam table properties.

The Attempt at a Solution


How can we know the pressure?
I think it is wrong to assume that the specific volume at 40C is the same with the specific volume at 2MPa. Any hint?
 
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physea said:

Homework Statement


1kg of water fills 151.1L of rigid container at pressure 2MPa. Then the container is cooled to 40C. What is the final pressure?

Homework Equations


Steam table properties.

The Attempt at a Solution


How can we know the pressure?
I think it is wrong to assume that the specific volume at 40C is the same with the specific volume at 2MPa. Any hint?
What is the specific volume of the water in the initial state? Here's a hint: In the final state, you will have a combination of liquid water and water vapor, having the same average specific volume as in the initial state. The final pressure should be easy to get, because the system will be saturated.
 
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