How Does Doubling the Force Affect the Speed of an Arrow?

  • Thread starter Thread starter EdoMan
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
Doubling the force exerted on an arrow by a bow increases its acceleration, as per Newton's second law. Given that the initial speed is 25.0 m/s and the distance remains constant, the kinematic equations can be applied to find the new final speed. The relationship between work, force, and kinetic energy is crucial, as the work done on the arrow translates into its kinetic energy. By applying these principles, one can determine the increased speed at which the arrow would leave the bow. Understanding these concepts is essential for solving the problem effectively.
EdoMan
Messages
1
Reaction score
0
An arrow, starting from rest, leaves the bow with a speed of 25.0m/s. If the average force exerted on the arrow by the bow were doubled, all else remaining the same, with what speed would the arrow leave the bow?


Any point in the right direction would help :) but I have been trying to solve this problem for the past half hour.

If anyone can work me through the problem that would be extra great.. i wish i can return the favor. TY


Homework Equations



Laws of Kinematics and Neutons Laws of Force(1 and 2)



The Attempt at a Solution



Im stuck

 
Physics news on Phys.org
when the force is doubled, so is the acceleration (since F=m*a) ..
it is said that all else remaining the same (x is the same for both cases) ..

and you have for your first case:
vo = 0 m/s , vf = 25 m/s , a = a m/s^2 , x = x m

for the second case:
vo = 0 m/s , vf = ? m/s , a = 2a m/s^2 , x = x m


hint: there is one of the kinematic equations you can use to find your answer .. :)
 
Try think about how the force and distance involved in accelerating the arrow is related to the work imposed on the arrow, and then how this work is related to kinetic energy and speed of the arrow.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top