How Does Electrolysis Affect pH in a HBr Solution?

AI Thread Summary
Electrolysis of a 1.30 L solution of 0.550M HBr with a current of 10.7 Amps converts some H+ ions to hydrogen gas (H2), affecting the solution's pH. After calculating the moles of H+ removed during 77 minutes, the resulting concentration of H+ is found to be 0.394M. The pH is then calculated as 0.405, which was initially deemed incorrect due to not accounting for the starting amount of H+. The correct approach requires subtracting the moles of H+ converted from the initial concentration. Ultimately, the discussion emphasizes the importance of considering both the initial and remaining concentrations of H+ in pH calculations.
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Homework Statement


A current of 10.7 Amps is applied to a 1.30 L solution of 0.550M HBr converting some of the H+ to H2(g), which bubbles out of solution. What is the PH of the solution after 77 minutes.


Homework Equations





The Attempt at a Solution


(10.7 C/s)(1 mol e/96485 C)(2 mol H+/2 mol e)(60s/min)(77 min) = .512 mol H+

.512 mol H+/1.30L = .394M H+
-log(.394M) = .405 = PH

This was incorrect
 
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You started with a certain amount of H+ in the solution. The electrolysis removed some. Now you need to calculate what's left.
 
I see will try, thank you
 
It worked, thank you
 
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