How Does Force Affect Javelin Momentum and Speed?

Thread starter almost__overnow
Start date Oct 22, 2006
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Momentum

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The discussion focuses on calculating the increase in momentum and speed of a javelin thrown by a 75kg athlete applying a 300 N force for 1.5 seconds. The impulse-momentum theorem indicates that the change in momentum equals the force multiplied by the time of application. Given that the initial momentum is zero, the increase in momentum is 450 kg·m/s. Consequently, using the mass of the javelin, the speed immediately after the throw is determined to be 225 m/s. Understanding these calculations is crucial for analyzing the effects of force on javelin performance.

Oct 22, 2006

almost__overnow

A 75kg javelin thrower applies a 300 N force to a 2.0kg javelin for 1.5 seconds.

a)what is the increase in momentum of the javelin?

b)what is the speed of the javelin immediately after the throw?

all i know is that ft = /\(mv) /\ is suppose to be a triangle.

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Oct 22, 2006

radou

Homework Helper

Look up the relation between change in momentum and impulse.

Oct 22, 2006

Office_Shredder

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Hint: the initial momentum is zero

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