How Does Friction Affect Mechanical Energy in a Bead Slide?

AI Thread Summary
The discussion focuses on the mechanics of a bead sliding on a curved wire, specifically analyzing the change in mechanical energy due to friction as it moves from point B to point C. The bead starts at a height of 4.9 m and comes to rest at 1 m, with kinetic energy calculated at point B being 24.01 J and potential energy at point C being 4.9 J. The participant correctly identifies that all energy must be conserved and attempts to relate kinetic and potential energy with friction. However, clarification is provided that the energy due to friction is indeed the change in mechanical energy, which is the sum of potential and kinetic energy. Understanding the relationship between these energy forms is crucial for solving the problem accurately.
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Homework Statement

A 0.5 kg bead slides on a curved wire, starting
from rest at point A.
The segment from A to B is frictionless, and
the segment from B to C is rough. The point
A is at height 4.9 m and the point C is at
height 1 m with respect to point B.
The acceleration of gravity is 9.8 m/s2 .If the bead comes to rest at C, find the change
in mechanical energy due to friction as it
moves from B to C.
Answer in units of J.



Homework Equations

K=.5mv^2, P=mgh



The Attempt at a Solution

Ok so here is where I'm at. I know that the Kenetic energy at point "B" will be 24.01 J. So once it it climbs up to point "c" the ball stops which means that the veolocity is 0 m/s. So there is no kenetic energy at point "C". At point "C" the potential energy will be P=mgh, (.5)(9.8)(1)= 4.9 J And the K= 0 Only at point "c". I know that all of the energy must be conserved so-- K at b= P at c+ K at c + Energy due to friction. So the "Change in Mechanical Friction" should be my energy due to friction. Yes? or No?
 
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notsam said:

Homework Statement

A 0.5 kg bead slides on a curved wire, starting
from rest at point A.
The segment from A to B is frictionless, and
the segment from B to C is rough. The point
A is at height 4.9 m and the point C is at
height 1 m with respect to point B.
The acceleration of gravity is 9.8 m/s2 .If the bead comes to rest at C, find the change
in mechanical energy due to friction as it
moves from B to C.
Answer in units of J.



Homework Equations

K=.5mv^2, P=mgh



The Attempt at a Solution

Ok so here is where I'm at. I know that the Kenetic energy at point "B" will be 24.01 J. So once it it climbs up to point "c" the ball stops which means that the veolocity is 0 m/s. So there is no kenetic energy at point "C". At point "C" the potential energy will be P=mgh, (.5)(9.8)(1)= 4.9 J And the K= 0 Only at point "c". I know that all of the energy must be conserved so-- K at b= P at c+ K at c + Energy due to friction. So the "Change in Mechanical Friction" should be my energy due to friction. Yes? or No?
You have the correct equation, but the wrong terms. From your equation, the energy due to friction is the change in mechanical energy, where mechanical energy is defined as P + K .
 
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