How Does Griffiths Derive x Using Creation and Annihilation Operators?

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Homework Help Overview

The discussion revolves around deriving the position operator \( x \) in the context of the harmonic oscillator using creation and annihilation operators, as presented in Griffiths' textbook. The original poster expresses difficulty in following the algebraic manipulations required to reach the desired form.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss solving simultaneous equations for the creation and annihilation operators to express position and momentum. One participant suggests defining constants to simplify the equations.

Discussion Status

The conversation indicates that some guidance has been provided regarding the algebraic approach to the problem. The original poster acknowledges the helpfulness of the suggestion, indicating a productive exchange.

Contextual Notes

There may be assumptions regarding the familiarity with the harmonic oscillator model and the specific equations used in Griffiths' example that are not explicitly stated in the discussion.

kuahji
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Find the expectation value of the potential energy in the nth state of the harmonic oscillator.

This is his example 2.5 in the book, he uses a\pm=1/Sqrt[2hmw](\mpip+mwx) to get x=Sqrt[h/2mw](a_{+}+a_{-})

My question how does he do this? I can't seem to make the algebraic manipulations to get it into that form to follow out his example.
 
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You have two equations, one for a_+ and one for a_-.

All you have to do is solve them simultaneously for x and p. i.e. Solve one for x, solve the other for p, plug the first into the second, etc. etc.

It may help to simplify things by defining some constants A and B such that:

a_{\pm}=Ap\mp Bx
 
That was easy enough, thank you for the tip!
 
No problem! :smile:
 

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