How Does Inserting a Dielectric Affect Capacitance and Potential?

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Inserting a dielectric affects capacitance and potential by changing the electric field between capacitor plates. The discussion revolves around determining the capacitance as a function of the position x, particularly when a dielectric is inserted. There is confusion regarding the capacitance at x=0, with participants debating whether it can be zero due to the lack of area. The need for a clear equivalent circuit to calculate total capacitance as a function of x is emphasized. Understanding the dielectric's role before and after insertion is crucial for solving the problem.
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Homework Statement


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Homework Equations

The Attempt at a Solution


I couldn't find the V(x).I don't know ho to write the equation.I think that it will be constant cause potential betwwen two plates should be constant... ?
 
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What is the energy in the capacitor as a function of x?
In other words, what is the capacitance as a function of x?
How is force related to this energy?
 
cnh1995 said:
What is the energy in the capacitor as a function of x?
In other words, what is the capacitance as a function of x?
How is force related to this energy?
##C_{eq}=(K+1)ε_0 \frac {xb} {d}## ? or maybe
##C=Kε_0 \frac {xb} {d}##
 
Arman777 said:
##C_{eq}=(K+1)ε_0 \frac {xb} {d}## ? or maybe
##C=Kε_0 \frac {xb} {d}##
I don't know the exact expression as I myself haven't worked it out yet, but check the answer at x=0. Is the capacitance zero at x=0?
 
cnh1995 said:
I don't know the exact expression as I myself haven't worked it out yet, but check the answer at x=0. Is the capacitance zero at x=0?
Yeah its
 
Arman777 said:
Yeah its
No, it isn't.
What is the capacitance for x=0?
 
cnh1995 said:
No, it isn't.
What is the capacitance for x=0?
Theres no area when x=0
 
Arman777 said:
Theres no area when x=0
How is this possible? Which area is considered for calculation of capacitance?
 
cnh1995 said:
How is this possible? Which area is considered for calculation of capacitance?
You are taking a-x I am just x
 
  • #10
Arman777 said:
You are taking a-x I am just x
But that doesn't make the total capacitance zero. You need to draw the equivalent circuit and find the total capacitance as a function of x.
 
  • #11
cnh1995 said:
But that doesn't make the total capacitance zero. You need to draw the equivalent circuit and find the total capacitance as a function of x.
I didnt understand
 
  • #12
Arman777 said:
I didnt understand
What is the dielectric between the plates before the new dielectric (with constant k) is inserted?
What is the capacitance when the new dielectric is not inserted at all?
 
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