How Does Kinetic Energy Affect Force in a 1D Atomic System?

AI Thread Summary
In a one-dimensional atomic system, an atom with kinetic energy K = 0.5*m*v**2 moves along the x-axis and is influenced by a magnetic field, creating a potential U(x) dependent on its position. The force on the atom, derived from the potential, is calculated as F = -dU/dx, revealing that the force is conservative since it relies solely on position. To escape the potential trap, the constant electronic force F0 must exceed the potential energy U0, with specific calculations needed for cases where the atom starts with K = 0 and K = U0/2 at x = 0. The discussion raises questions about how the presence of the electrostatic force modifies the potential energy landscape. Understanding these interactions is crucial for determining the conditions for the atom's escape from the trap.
MaxManus
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Homework Statement


We addrewss a one dimensional system. An atom moves along the x-axis with a kinetic energy K = 0.5*m*v**2. In the range -x0<x<x0 the atom enters the trap, and is affected by a magnetic fiels. The interaction with the magnetic field gives rise to a potential U(x) which we model:

for abs(x)>= x0, U(x) = U0
for abs (x) < x0, U(x) = U0*abs(x)/x0

a) Find the force F(x) on the atom from the magnetic field. Is this force conservative?

Let us also assume that the atom is charged and also subject to a constant electronic force, F0 acting in the positive x-direction

b) If the atom has kinetic energy K = 0 at x = 0, how laarge must F0 be in order for the atom to escape? And if the kinetic energy is K = U0/2 at x = 0, how large must F0 then be in order for the atom to escape.

Homework Equations





The Attempt at a Solution



a)
F = -dU/dx

F = 0 for abs(x) >= x0
F = U0/x0 for -x0<x<0
F = -U0/x0 0for 0<x<x0

The force is conservative for it is only dependent on the position

b) Here I need some help.
Is the idea that the force must give the atom larger total energy than u0?
 
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MaxManus said:
b) Here I need some help.
Is the idea that the force must give the atom larger total energy than u0?

Not sure if that would be the case or not.

The way I think about it is, how is the potential modified due to the presence of the constant electrostatic force?
 
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