Hi bjacoby-
You have brought up some interesting points in your post. The betatron is actually a very good example of magnetic induction, because in this case the electric field is in vacuum (free space), and not constrained to a wire, like in a transformer.
First, I would like to discuss retardation and signal propagation in magnetic materials. As you probably know, signals in vacuum travel at the speed of light; c = 1/sqrt(ε0μ0), where ε0 and μ0 are the permittivity and permeability of free space. In glass, the apparent speed of light is 1/sqrt(ε ε0μ0) = c/√ε = c/n, where ε is the relative permittivity of glass, and n its index of refraction. The same thing happens in magnetic materials. The speed of signal propagation in a ferromagnetic material is v = c/√μ, where μ is the relative permeability. For soft iron and transformer iron, μ ≈5000, so v ≈ c/70 (neglecting other factors). So the signals travel through iron √5000 = 70 times (or more) slower than the speed of light. So any signal traveling from the primary coil to the secondary at the speed of light must be traveling independent of the presence of the iron. But would there be a signal without the iron?
This delay can be demonstrated in a torus. Consider a flexible ferrite torus of major radius 5 cm, minor radius 3 mm, and μ =5000. Put several turns of wire on the right hand side, and several turns on the left. A fast pulse of the left hand side will take about 36 nsec to reach the right side via the ferrite, vs. less than 1 nsec by direct speed of light propagation. Now visualize the following: Pick up the torus with each coil between your forefingers and thumbs. Now twist the coil in your right hand 90 degrees so that the planes of the two coils are orthogonal. Will there still be a pulse traveling from the left coil to the right coil, and if so how did it get there, and how fast? If the ferrite torus were removed, there is no coupling from one coil to the other because of orthogonality. So the signal either travels inside the ferrite, or on its surface, but is not line of sight. It has to be causal, because with no ferrite, there would be no signal.
In jbell’s equation, the ∂B/∂t in the iron at the beam torus in the betatron creates the longitudinal (accelerating) E field in the beam tube torus. This is a causal relation (see above). Furthermore, a DC (fixed) E field outside the iron cannot create a ∂B/∂t inside the iron (∂B/∂t = -curl E). The ∂B/∂t at the beam torus is retarded from the ∂B/∂t created in the iron at the primary coil, and travels to the beam torus at the velocity c/√μ. So the E field in the beam torus must be caused by the ∂B/∂t field in the iron, and not by direct coupling to the primary coil.
Bob S