How does mass affect the outcome of a head-on elastic collision?

AI Thread Summary
In a head-on elastic collision, the mass of the moving body (m1) significantly influences the outcomes based on its behavior post-collision. If m1 stops, it must be greater than m2. If m1 rebounds with nearly the same speed, it indicates that m1 is slightly larger than m2. When m1 continues in the same direction with nearly the same speed, it suggests m1 is much smaller than m2. The conservation of momentum and energy principles are essential for analyzing these scenarios.
phyzwiz69
Messages
4
Reaction score
0

Homework Statement


A rapidly moving body of mass m1 strikes a body of mass m2 at rest in a head-on elastic collision. How does m1 compare with m2 if the first body (m1)
a. stops?
b. comes back along its path at very nearly the same speed it had before the collision?
c. continues along in the same direction with very nearly the same speed that it had before the collision?
d. comes back along its path with a very small speed?
e. continues along its path with a very small speed?


Homework Equations





The Attempt at a Solution


 
Physics news on Phys.org
Hi there,

The two laws of conservation will help you solve this problem: energy conservation, and momentum conservation.

Cheers
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
16
Views
3K
Replies
5
Views
2K
Replies
4
Views
5K
Replies
12
Views
3K
Replies
4
Views
3K
Replies
2
Views
2K
Replies
5
Views
3K
Back
Top