How Does Momentum Affect Collision Damage?

  • Thread starter Thread starter KatieLynn
  • Start date Start date
  • Tags Tags
    Damage Momentum
AI Thread Summary
In determining collision damage, the discussion emphasizes the importance of total momentum change per unit time, suggesting that a rapid change in momentum results in greater damage. Participants agree that a longer duration of momentum change would lead to less damage. The conversation centers around the relationship between momentum change and the time over which it occurs. Overall, the consensus leans towards the idea that the rate of momentum change is crucial in assessing collision impact. Understanding these dynamics is essential for analyzing collision outcomes effectively.
KatieLynn
Messages
64
Reaction score
0

Homework Statement



What is more important in determining the amount of damage an object sustains in a collision?



A. Total momentum Change

B. Total momentum change per unit time

C. None of these

D. Both of these

Homework Equations





The Attempt at a Solution



I think it is is B because if the momentum change is over a very long period of time then there wouldn't be as much damage as if the momentum change happened over a short period of time. Do you agree?
 
Physics news on Phys.org
ya. I do.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Ambiguous question on momentum and how it works...
Replies
13
Views
1K
Spring momentum conservation problem
Replies
4
Views
2K
Potential Energy - 2D inelastic collision - ballistic pendulum
Replies
10
Views
2K
How Does Angular Momentum Conservation Affect Asteroid Collision Dynamics?
7
Replies
335
Views
13K
Work done during a collision -- Change in Kinetic Energy & change in Momentum
Replies
1
Views
2K
Elastic collision of particle and rotating disc
Replies
7
Views
2K
Kinetic energy and momentum of two satellites colliding
Replies
8
Views
3K
Why is momentum conservation always true in a collision?
Replies
4
Views
2K
Explaining the Impact of Momentum and Collision on Damage in Head-On Collisions
Replies
4
Views
2K
Correct statement about perfectly elastic collision
Replies
15
Views
4K

Hot Threads

Recent Insights

Back
Top