How Does Phasor Addition Simplify Trigonometric Expressions?

  • Thread starter Thread starter smallwa
  • Start date Start date
  • Tags Tags
    Addition
AI Thread Summary
The discussion focuses on simplifying the expression x(t)=5cos(wt)+5cos(wt+120)+5cos(wt-120) using phasor addition. Participants note that when applying the phasor addition rule, the result simplifies to zero. This indicates that the combined effect of the three cosine terms cancels out completely. The final conclusion is that x(t) can be expressed as x(t)=0. The use of phasors effectively demonstrates how trigonometric expressions can be simplified.
smallwa
Messages
2
Reaction score
0

Homework Statement


Define x(t)=5cos(wt)+5cos(wt+120)+5cos(wt-120)

simplify x(t) into the standard sinusoidal form:x(t)= A cos(wt+phase).Use phasors to do the algebra.

Homework Equations


The Attempt at a Solution


i know it needs to use phasor addition rule.
First,i represent x1(t),x2(t),x3(t) by the phasors,and then add them together
however the result is 0,then i don't know to dothanks a lot:))
 
Last edited:
Physics news on Phys.org
smallwa said:

Homework Statement


Define x(t)=5cos(wt)+5cos(wt=120)+5cos(wt-120)

Correct x(t), please!


ehild
 
ehild said:
Correct x(t), please!


ehild

sorry,corrected
 
The result is really zero. So write x(t)=0.

ehild
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Electrical: Reduce the expression to the form V_mcos(wt+theta)
Replies
3
Views
4K
Adding three SHM oscillations of equal frequency?
Replies
4
Views
2K
How Does Circular Polarization Arise in String Wave Motion?
Replies
3
Views
2K
Phasor Addition Simplify 5cos(wot+90°)+5cos(wot-30°)+5cos(wot-120°): Solve
Replies
3
Views
2K
Simple harmonic motion displacement equation confusion
Replies
8
Views
6K
I LRC Series Circuit with an AC Source
Replies
10
Views
1K
Phasor representation of plane wave propagation
Replies
12
Views
9K
Engineering Electrical Engineering - AC Circuits Phasors
Replies
2
Views
2K
Which Frequencies Will a Listener Not Hear from Two Variable-Frequency Speakers?
Replies
8
Views
3K
1D Angular Motion with different velocity stages
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top