How Does Phonon Contribution Affect Heat Capacity in Liquid Helium Below 0.6K?

precondition
Messages
57
Reaction score
0
Below 0.6K the heat capacity of liquid He is well represented by the equation
Cv=(9.819 x 10^-3 K^-3)NkT^3
Given that transverse shear waves cannot propagate in a liquid, predict the phonon contribution to the heat capacity of He from the data
c=238 m/s (speed of sound in liquid He)
p=0.145 g cm^-3 (density of liquid He)

......difficult...T_T
 
Physics news on Phys.org
x is supposed to be multiplication
N number of molecules
k Boltzmann's constant
T temperature in kelvin
Cv heat capacity
 
I find this rather hard to follow since I'm not getting that the specific heat has a T^3 dependence at low temperatures for a system of massless bosons (read: the phonons). I'm getting that U ~ T^3 and, then C_v ~ T^2, so I'm a little confused. I also haven't slept much the past two weeks so I could be doing something silly here.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top