How Does Projectile Motion Affect Speed and Angle on Impact?

AI Thread Summary
A particle moves between two parallel walls, hitting the opposite wall at the same height while traveling at a constant speed of 9.2 m/s. The problem involves calculating the speed and angle of impact, with gravity affecting the vertical motion. Attempts to solve for the final speed yielded incorrect results, indicating a misunderstanding of the projectile motion equations. Suggestions include focusing on the trajectory between the midpoint and the wall to determine the vertical speed at impact. Understanding the relationship between vertical and horizontal components is crucial for accurate calculations.
Beanie
Messages
32
Reaction score
0

Homework Statement


A particle travels between two parallel ver- tical walls separated by 25 m. It moves to- ward the opposing wall at a constant rate of 9.2 m/s. It hits the opposite wall at the same height.

The acceleration of gravity is 9.8 m/s2 .

(IMAGE FOR CLARIFICATION ATTACHED)

a) What will be its speed when it hits the opposing wall?
b) At what angle with the wall will the particle strike?

Homework Equations


Vf=vi+at
d=vit=.5at^2
vf^2=Vi^2+2ad

The Attempt at a Solution


I've tried this problem (a) many times in many different ways, but continue to get it wrong. I have not yet been able to do problem (b) because of the lack of information (I need to complete a to do b)

Attempts:
The first way I tried was to find the time and then plug it into the second equation described above using d=25, t=2.7, a=-9.8. This resulted in a velocity of 22.52m/s. However this velocity is wrong.

The second way I tried was to find t (same as above) and then use Vx=9.2 as well as t=2.7 to calculate Vy. I found this to be 26.62. I then used the pythagorean theorem using Vx and Vy to find V. My final answer was 28.164m/s. This velocity answer was also wrong.

Any suggestions on where I am going wrong? Are there any other ways of calculating velocity?
 

Attachments

  • Screen Shot 2015-08-31 at 6.03.55 PM.png
    Screen Shot 2015-08-31 at 6.03.55 PM.png
    9.7 KB · Views: 479
Physics news on Phys.org
Start by figuring out how the final components of the velocity are related to the initial components when a projectile returns to the same height from which it was launched. Also, it seems that you have found the time of flight. Can you find the initial vertical component of the velocity?
 
Beanie said:

Homework Statement


A particle travels between two parallel ver- tical walls separated by 25 m. It moves to- ward the opposing wall at a constant rate of 9.2 m/s. It hits the opposite wall at the same height.

The acceleration of gravity is 9.8 m/s2 .

(IMAGE FOR CLARIFICATION ATTACHED)

a) What will be its speed when it hits the opposing wall?
b) At what angle with the wall will the particle strike?

Homework Equations


Vf=vi+at
d=vit=.5at^2
vf^2=Vi^2+2ad

The Attempt at a Solution


I've tried this problem (a) many times in many different ways, but continue to get it wrong. I have not yet been able to do problem (b) because of the lack of information (I need to complete a to do b)

Attempts:
The first way I tried was to find the time and then plug it into the second equation described above using d=25, t=2.7, a=-9.8. This resulted in a velocity of 22.52m/s. However this velocity is wrong.

The second way I tried was to find t (same as above) and then use Vx=9.2 as well as t=2.7 to calculate Vy. I found this to be 26.62. I then used the pythagorean theorem using Vx and Vy to find V. My final answer was 28.164m/s. This velocity answer was also wrong.

Any suggestions on where I am going wrong? Are there any other ways of calculating velocity?

Draw a dotted line on your diagram that's exactly halfway between the two walls. Start by focusing only on the part of the particle's trajectory that's between this dotted line and the wall on the right (ignoring for now the other half of the trajectory to the left). Can you use the equations you listed above to determine the vertical speed of the particle at the time it reaches the right wall?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top