How Does Reversing Current Direction Affect Magnet Position in a Coil?

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Reversing the current direction in a cylindrical coil changes the magnetic polarity, making side A the north pole and side B the south pole. When the current is reversed, the permanent magnet will move towards side B and settle with its north end aligned with the north pole of the coil's B side. This behavior is analogous to two permanent magnets attracting each other at their respective poles. The initial position of the magnet affects its final resting place based on the polarity of the coil. Understanding this interaction is crucial for applications involving electromagnetism and magnetic positioning.
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Hello all,

In the sketch attached below, I have a cylindrical coil with a cylindrical permanent magnet located in the center (assume the magnet can only move in the axial A-B direction). It is my understanding that if the coil had current flowing through it so that side A was the south pole and side B was the north, and the permanent magnet started in the position shown, the permanent magnet would move towards A and settle in the center of the coil (please correct me if that is inaccurate). What I can't visualize is where the permanent magnet would settle (again starting from the position shown) if the current was reversed and the A side was the North pole and the B side was the south pole... Would the north end of the magnet (the outside surface) line up with the outside surface of the B side on the coil?

Thanks for your help

- confused mech engineer
 

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carpekd said:
Hello all,

Would the north end of the magnet (the outside surface) line up with the outside surface of the B side on the coil?

Yes. It would be just like two permanent magnets stuck together at a single N-S edge.
 
Thanks for clearing that up!
 
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