How Does Temperature Affect NO2 Formation in Combustion?

AI Thread Summary
Temperature significantly influences the formation of NO2 during combustion, as higher temperatures make the formation of certain trace gases thermodynamically favorable. To calculate the equilibrium partial pressure of NO2 at 1 atm and 1600 K, it is essential to determine the partial pressures of nitrogen (N) and oxygen (O2) first. The equilibrium constant (K) for the reaction can be calculated assuming an initial presence of only NO2, allowing for the derivation of other gas pressures through stoichiometry. Clarity in the problem statement is necessary for accurate calculations. Understanding these relationships is crucial for analyzing combustion processes effectively.
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Homework Statement



We discussed the fact that the formation of some trace gases is thermodynamically unfavorable at low temperature, but more favorable at elevated temperatures. Using the values for delta G and delta H in the notes, calculate the equilibrium partial pressure of NO2 during combustion at at 1 atm and T = 1600 K.


The Attempt at a Solution


Just getting stuck on what the partial pressure of [N] and [O2] are.
 
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Calculate K for the reaction, assume you start with just NO2, then pressures of other gasses can be calculated from the reaction stoichiometry.

The wording seems to be unclear.

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Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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