How Does the Angle of Incline Affect Current in a Sliding Rod Experiment?

AI Thread Summary
The discussion revolves around calculating the current flowing through a sliding aluminum rod on tilted conducting rails in a magnetic field. The rod, weighing 0.22 kg and 1.6 m long, slides down at a constant velocity while the rails are inclined at 30 degrees. Initial confusion arises regarding the use of angles in the force and current equations, particularly in relation to gravitational acceleration and the constant velocity condition. After some calculations, it is clarified that the correct angle to use in the sine function for the magnetic force is 60 degrees, not 30 or 90 degrees. The participant ultimately resolves their confusion and indicates they have found the solution.
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:rolleyes: The two conducting rails in the drawing are tilted upwards so they make an angle of 30.0° with respect to the ground. The vertical magnetic field has a magnitude of 0.048 T. The 0.22 kg aluminum rod (length = 1.6 m) slides without friction down the rails at a constant velocity. How much current flows through the bar?
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ok so I'm really completely lost here, but let me give you guys what I'm thinking, see if you could lead me in the right direction

I'm expecting that you don't use that 30 degrees as part of F= ILB sin(theta), but rather you use it to find force with F=ma right? if that's the case, how would you find the acceleration? would it just be 9.8 for gravity, or would it be something else because you're not going straight down... but then i have a problem with velocity being constant, which means there would be no acceleration... but there has to be gravity...

(i'm sorry if i seem all over the place :confused: just confused)

so here's what I've done and it didn't work

F=ma

F= .22 * 9.8sin30
F= 1.078
F= I L B sin(theta)
1.078= I 1.6*.048 sin 90
I =14.036

thats not the right answer, but to me that seems the only logical way to go about answering this problem... any info would help thank you!
 
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Nevermind i figured it out, its sin(60), not sine of 30 or 90... you can kill this thread if you wish!
 
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