utkarshakash
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Homework Statement
The mean life of a certain radioactive element is 6 hrs. By what fraction will its initial activity decrease over a time period of 5 hrs.
Homework Equations
t_{avg}=\frac{1}{k}
Initial Activity = kN_{0}
Final Activity = kN_{t}
The Attempt at a Solution
From eqn 1 I obtain the value of k = 0.166 hr^{-1}
Since I have to calculate the fraction of initial and final activity
Dividing eqn 2 by 3
\frac{Initial Activity}{Final Activity}=\frac{N_{0}}{N_{t}}
So this means now I have to calculate \frac{N_{0}}{N_{t}} which will be my answer
So using first order kinetics equation
k=\frac{2.303}{5}log\frac{N_{0}}{N_{t}}
Plugging the known values I get \frac{N_{0}}{N_{t}}=2.3006
which is unfortunately incorrect. But how?