How Does Thermodynamics Explain Power Generation in Motorcycle Engines?

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SUMMARY

This discussion focuses on the thermodynamic principles governing power generation in motorcycle engines, specifically through adiabatic expansion. The participants analyze the work done during this process using the formula W=(p2V2 - p1V1)/(γ - 1), where p1 is the initial pressure (15.0 atm), V1 is the initial volume (50.0 cm³), and γ is the heat capacity ratio (7/5). The final volume (V2) is clarified as 250 cm³, and the time for expansion is established as half of the total cycle time at 4000 rpm. The discussion also highlights the importance of understanding engine mechanics for accurate calculations.

PREREQUISITES
  • Understanding of thermodynamics, specifically adiabatic processes
  • Familiarity with motorcycle engine mechanics
  • Knowledge of the heat capacity ratio (γ) for diatomic gases
  • Basic proficiency in using formulas for work done in thermodynamic processes
NEXT STEPS
  • Study the principles of adiabatic expansion in thermodynamics
  • Learn about the mechanics of motorcycle engines and their components
  • Explore the calculations involved in thermodynamic work using real-world examples
  • Investigate the differences between various engine types, including radial engines
USEFUL FOR

Engineers, physics students, motorcycle enthusiasts, and anyone interested in the thermodynamic principles of power generation in internal combustion engines.

Kelvin
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In a motorcycle engine, after combustion occurs in the top of the cylinder, the piston is forced down as the mixture of gaseous products undergoes an adiabatic expansion. Find the average power involved in this expansion when the engine is running at 4000 rpm, assuming that the gauge pressure immediately after combustion is 15.0 atm, the initial volume is 50.0 cm^3, and the volume of the mixture at the bottom of the stroke is 250 cm^3. Assume that the gases are diatomic and that the time involved in the expansion is one-half that of the total cycle.

I know work done in adiabatic process is
W=\frac{p_2 V_2 - p_1 V_1}{\gamma - 1}

and for adiabatic process,
p_1 V_1^{\gamma} = p_2 V_2^{\gamma}

so V_1 = 50.0 \hbox{ cm^3}, p_1 = 15.0 \hbox{ atm},
\gamma = \frac{7}{5}

but what is the final volume V_2, which I need to determine p_2?
 
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Kelvin said:
... the initial volume is 50.0 cm^3, and the volume of the mixture at the bottom of the stroke is 250 cm^3.
Isn't the final volume given?
 
actually, I don't even know what a motorcycle is, and how the cylinder looks like ...


what is meant by "the volume of the mixture at the bottom of the stroke" ?
 
the volume of the mixture at the bottom of the stroke is the final Volume

This is a motorcycle :bugeye:
 
sorry, I made typo mistakes
I mean I don't know how "motorcycle engine" works, and how does the "cyclinder" looks like...
 
Last edited:
so the assumption that "the expansion is one-half that of the total cycle" is wrong? it should be 1/4 ?
 
oh...I've found the answer :D
so...let me redo the problem
 
oh I got it correct
thanks a lot
my "picture of engine" is completely wrong ...
 

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