How Does Torque Maintain Equilibrium in a Ladder Supported by Two People?

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The discussion centers on the mechanics of a ladder supported by two people, focusing on how torque maintains equilibrium. Initially, when both individuals support the ladder, the forces are balanced, with person A providing a force of 120N and person B 280N. Once person A releases the ladder, the equilibrium is disrupted, necessitating that person B generates a torque to counteract the weight of the ladder. The torque required from person B to keep the ladder horizontal is calculated to be 300Nm. Understanding the distinction between force and torque is crucial for solving the problem effectively.
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Homework Statement


A uniform ladder AC weight 400N & length 3.5 m is held horizontally by 2 people. One person supports at A and the other at B, a distance 1m away from C.
1. Calculate the supporting force provided by the person at A. (I managed to do this one and the answer is 120N)
2. The person at A releases the ladder. Calculate the torque which the person at B must provide in order to keep the ladder horizontal.

The diagram can be found here (scroll down to see diagram)
http://www.thestudentroom.co.uk/showthread.php?t=1780861

I am having some problems with question 2. The answer to question 2 is 300Nm :)

Homework Equations





The Attempt at a Solution


It is known that the supporting force at A is 120N when the end of the ladder (at A) has not been released, this means that the supporting force at B is 280N (400N-120N). However, I do not understand why the question asked for torque, I thought torque would require two forces which form a couple? Or am I having a gross misconception? Or does the torque here refers to the moment? If the ladder is horizontal, the ladder should be in equilibrium, hence the total upward forces should equal to the total downward forces. So does this mean that the new supporting force at B should also be 400N?

Please include explanations along with your solution, thanks a million! :D
 
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jiayingsim123 said:

The Attempt at a Solution


It is known that the supporting force at A is 120N when the end of the ladder (at A) has not been released, this means that the supporting force at B is 280N (400N-120N). However, I do not understand why the question asked for torque, I thought torque would require two forces which form a couple? Or am I having a gross misconception? Or does the torque here refers to the moment? If the ladder is horizontal, the ladder should be in equilibrium, hence the total upward forces should equal to the total downward forces. So does this mean that the new supporting force at B should also be 400N?

Please include explanations along with your solution, thanks a million! :D

With the system as shown in the diagram, the ladder is in equilibrium. So all three forces help to provide that equilibrium.

When person A let's go, the system is not in equilibrium anymore. The sum of the moments about any point is not zero anymore.

For it to remain in equilibrium, the person at B will need to provide a torque to balance out the torque due to the weight.
 
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